Solve the following:$\frac{-2}{3} -3 \times \frac{-2}{3} -2$

Given :

The given expression is $\frac{-2}{3} -3 \times \frac{-2}{3} -2$.

To do :

We have to solve the given expression and find the value.

Solution :

$\frac{-2}{3} -3 \times \frac{-2}{3} -2 = \frac{-2}{3} -1 \times -2 -2$

                                                               $ = \frac{-2}{3} +2 - 2$

                                                               $ = \frac{-2}{3}$

Therefore, the value of $\frac{-2}{3} -3 \times \frac{-2}{3} -2$ is $\frac{-2}{3}$.

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Updated on: 10-Oct-2022

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