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Solve the following: $\frac{-3}{8} -(\frac{-6}{20})$
Given: $\frac{-3}{8} -(\frac{-6}{20})$
To do: Solve the given expression.
Solution: $\frac{-3}{8} -(\frac{-6}{20})$
[Open the bracket]
= $\frac{-3}{8} +\frac{6}{20}$
LCM of 20 and 8 is 40
=$\frac{-3\times5+6\times2}{40}$
=$\frac{-15+12}{40}$
=$\frac{3}{40}$
Therefore, the solution is $\frac{3}{40}$
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