Solve the following equations:

a) $ 2 y+\frac{5}{2}=\frac{37}{2} $

b) $ 5 t+28=10 $
c) $ \frac{a}{5}+3=2 $

Given: The three equations are

a) $ 2 y+\frac{5}{2}=\frac{37}{2} $

b) $ 5 t+28=10 $

c) $ \frac{a}{5}+3=2 $

To find:  We have to solve the equations(variables) given.

Solution:

a) $2y + \frac{5}{2} = \frac{37}{2}$

$2y = \frac{37}{2} - \frac{5}{2} = \frac{(37-5)}{2}$

$2y = \frac{32}{2}= 16$

$y = 1\frac{6}{2} = 8$

$y = 8$

b) $5t + 28 = 10 $

$5t = 10 - 28$

$5t = - 18$

$t = \frac{-18}{5}$

c) $\frac{a}{5} + 3 = 2$

$\frac{a}{5} = 2 - 3 = -1$

$a = 5 \times - 1$

$a = -5$ 

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Updated on: 10-Oct-2022

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