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Solve the following equation:$28=4+3(t+5)$.
Given :
The given equation is $28 = 4+3(t+5)$.
To do :
We have to find the value of t.
Solution :
$28 = 4+3(t+5)$
$28 = 4+3(t)+3(5)$
$28 = 4+3t+15$
$28 = 3t+19$
$3t = 28-19$
$3t = 9$
$t = \frac{9}{3}$
$t = 3$.
The value of t is 3.
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