Solve the following
$ \frac{-4}{5} \times \frac{3}{7} \times \frac{15}{16} \times\left(\frac{-14}{9}\right) $

Given:  $(\frac{-4}{5}) \times \frac{3}{7} \times \frac{15}{16} \times (\frac{-14}{9})$

To Find : We have to  find the value of $(\frac{-4}{5}) \times \frac{3}{7} \times \frac{15}{16} \times (\frac{-14}{9})$.

Solution:

Rearranging the terms, we get 

$\frac{-4}{5} \times \frac{15}{16}  \times \frac{3}{7} \times \frac{-14}{9}$

We know that $4 \times 4=16$, 5 $\times$ 3 =15, 7 $\times$ 2=14 and 3 $\times$ 2=9. Therefore,

$\frac{-4}{5} \times \frac{15}{16}  \times \frac{3}{7} \times \frac{-14}{9}$

= $\frac{-1}{1}\times \frac{3}{4} \times \frac{1}{1}\times \frac{-2}{3}$

=$\frac{-3}{4} \times \frac{-2}{3}$ (negative multiplied with positive gives negative)

=$\frac{6}{12}$ (-ve multiplied with -ve gives +ve)

=$\frac{1}{2}$

Therefore the solution of the expression is $\frac{1}{2}$