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Solve the expression:$\frac{x-7}{3} = \frac{x-1}{5}$
Given: $\frac{x-7}{3} = \frac{x-1}{5}$
To do: Find for $x$
Solution:
$\frac{x-7}{3} = \frac{x-1}{5}$
By cross multiplication:
$5(x-7) = 3(x-1)$
$5x -35 = 3x - 3$
$5x - 3x = -3 + 35$
$2x = 32$
$x = 16$
Therefore, the value of $x$ isAdvertisements