Solve the equation$x^2+ 6x - (a^2 +2a - 8) = 0$.

Given:  $x^2+ 6x - (a^2 +2a - 8) = 0$.

To do:  Solve the equation.

Solution:

$x^2 + 6x - (a^2 +2a - 8) = 0$

=$ x^2+ 6x - (a^2 +2a + 1- 9) = 0$

=$ x^2 + 6x - (a^2 +2a + 1) + 9 = 0$

=$ x^2 + 6x  + 9- (a^2 +2a + 1) = 0$

= $x^2 + 2\times3x + 3^2 - (a+ 1)^2 = 0$

= $(x+3)^2 - (a+1)2$

$x+3 = -(a+1)$ or $(a+1)$

or $x = -a-1-3$ or $a+1-3$

or$ x = -a-4 $or $a + 2$

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

108 Views

Kickstart Your Career

Get certified by completing the course

Get Started