Solve the equation
$2x+\frac{1}{3}=3x+\frac{4}{6}$

Given: $2x+\frac{1}{3}=3x+\frac{4}{6}$

To find:  We have to find the value of $x$.

Answer:

$2x+\frac{1}{3}=\frac{3x+4}{6}$

$3x - 2x = \frac{1}{3} - \frac{4}{6}$

                 = $\frac{1}{3} - \frac{2}{3}$

$x =\frac{1-2}{3} = \frac{-1}{3}$

So $x = \frac{-1}{3}$ is the solution.

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Updated on: 10-Oct-2022

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