Solve the equation $3x+\frac{1}{5}=2–x $ and check the answer.

Given: The given equation is $3x+\frac{1}{5} = 2-x$

To find: We have to find the value of x and check the answer.

Solution:

$3x+\frac{1}{5}=2–x$

=> $3x + x = 4x = 2 - \frac{1}{5}$

=> $\frac{(10-1)}{5} = \frac{9}{5}$

So, $4x = \frac{9}{5}$ or  

$x = \frac{9}{5}$ $\times$ $\frac{1}{4}$ = $\frac{9}{20}$

=> $x$ = $\frac{9}{20}$ 

Checking: 

=> $3x+\frac{1}{5}=2–x$

LHS = $3(\frac{9}{20}) + \frac{1}{5}  = \frac{27}{20} + \frac{4}{20} = \frac{31}{20}$

RHS = $2 - x = 2 - \frac{9}{20} = \frac{(40 - 9)}{20} = \frac{31}{20}$

LHS = RHS  Hence Verified

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Updated on: 10-Oct-2022

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