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Solve:3/8 + 9/16 - 1/8.
Given: $\frac{3}{8} \ +\ \frac{9}{16} \ -\ \frac{1}{8}$
To find: We have to find the value of $\frac{3}{8} \ +\ \frac{9}{16} \ -\ \frac{1}{8}$
Solution:
$\frac{3}{8} \ +\ \frac{9}{16} \ -\ \frac{1}{8}$
= $\ \frac{3\ \times \ 2\ +\ 9\ \times \ 1\ -\ 1\ \times \ 2}{16}$
= $\frac{6\ +\ 9\ \ -\ 2}{16}$
= $\frac{15\ -\ 2}{16}$
= $\ \frac{13}{16}$
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