Solve following linear equation:

($ 2(x-2)-3(x-3)=5(x-5)+4(x-8) $

Given:

Given equation is $2(x-2)-3(x-3)=5(x-5)+4(x-8)$.

To do:

We have to find the value of $x$.

Solution:

$2(x-2)-3(x-3)=5(x-5)+4(x-8)$

$2(x)-2(2)-3(x)-3(-3)=5(x)-5(5)+4(x)-4(8)$

$2x-4-3x+9=5x-25+4x-32$

$-x+5=9x-57$

$9x+x=5+57$

$10x=62$

$x=\frac{62}{10}$

$x=\frac{31}{5}=6.2$

The value of $x$ is $\frac{31}{5}=6.2$.

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Updated on: 10-Oct-2022

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