Solve $ : 5 x-\left(4 x+\frac{5 x-4}{7}\right)=\frac{4 x-14}{3} $

Given:

Given equation is $5x-(4x+\frac{5x-4}{7})=\frac{4x-14}{3}$.

To do:

We have to find the value of $x$.

Solution:

$5x-4x-\frac{5x-4}{7}=\frac{4x-14}{3}$

$x-\frac{5x-4}{7}=\frac{4x-14}{3}$

$\frac{7x-(5x-4)}{7}=\frac{4x-14}{3}$

$\frac{2x+4}{7}=\frac{4x-14}{3}$

$3(2x+4)=7(4x-14)$   (On cross multiplication)

$6x+12=28x-98$

$28x-6x=12+98$

$22x=110$

$x=\frac{110}{22}$

$x=5$

The value of $x$ is $5$.

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

35 Views

Kickstart Your Career

Get certified by completing the course

Get Started