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Solve: $3 \sqrt{3}+2 \sqrt{27}+\frac{7}{\sqrt{3}}$.
Given: $3\sqrt{3}+2\sqrt{27}+\frac{7}{\sqrt{3}}$.
To do: To solve: $3\sqrt{3}+2\sqrt{27}+\frac{7}{\sqrt{3}}$.
Solution:
$2\sqrt{27} =2\sqrt{3\times3\times3}=6\sqrt{3}$
$\frac{7}{\sqrt{3}}=\frac{(7\times\sqrt{3})}{(\sqrt{3}\times\sqrt{3})}=\frac{7\sqrt{3}}{3}$
Now,
$ 3\sqrt{3}+2\sqrt {27}+\frac{7}{\sqrt{3}}$
$=3\sqrt{3}+6\sqrt{3}+( \frac{7\sqrt{3}}{3})$
$=9\sqrt{3}+( \frac{7\sqrt{3}}{3})$
$=\frac{( 27\sqrt{3}+7\sqrt{3})}{3}$
$=\frac{34\sqrt{3}}{3}$
Thus, $3\sqrt{3}+2\sqrt{27}+\frac {7}{\sqrt{3}}=\frac {34\sqrt{3}}{3}$.
Updated on: 10-Oct-2022
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