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Solve: $(-3)^{4}\p( \frac{-2}{3})^{4}$.
Solution:
$(-3)^{4}\div( \frac{-2}{3})^{4}$
$=\frac{( -3)^4}{( \frac{-2}{3})^{4}}$
$=( \frac{-3\times3}{-2})^4$
$=( \frac{9}{2})^4$
$=\frac{9\times9\times9\times9}{2\times2\times2\times2}$
$=\frac{6561}{16}$
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