Solve: $(-3)^{4}\p( \frac{-2}{3})^{4}$.

Solution:

$(-3)^{4}\div( \frac{-2}{3})^{4}$

$=\frac{( -3)^4}{( \frac{-2}{3})^{4}}$

$=( \frac{-3\times3}{-2})^4$

$=( \frac{9}{2})^4$

$=\frac{9\times9\times9\times9}{2\times2\times2\times2}$

$=\frac{6561}{16}$

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Updated on: 10-Oct-2022

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