Solve $-2(xy^2-x^2y)+5-xy$ when $x=-5$ and $y=5$.

Given:

$-2(xy^2-x^2y)+5-xy$

To do:

We have to find the value of $-2(xy^2-x^2y)+5-xy$ when $x=-5$ and $y=5$.

Solution:

We know that,

$[(+)\times(+)=(-)\times(-)=(+)]$

$[(+)\times(-)=(-)\times(+)=(-)]$

To find the value of $-2(xy^2-x^2y)+5-xy$ when $x=-5$ and $y=5$, we substitute $x=-5$ and $y=5$ in $-2(xy^2-x^2y)+5-xy$.

Therefore,

$-2(xy^2-x^2y)+5-xy=-2[(-5)(5)^2-(-5)^2(5)]+5-(-5)(5)$

$=-2[(-5)(25)-(25)(5)]+5-(-25)$

$=-2[-125-125]+5+25$

$=-2(-250)+30$

$=500+30$

$=530$

Hence, the value of $-2(xy^2-x^2y)+5-xy$ when $x=-5$ and $y=5$ is $530$.

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Updated on: 10-Oct-2022

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