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Simplify the following :$3 \frac{7}{9} + 5 \frac{7}{8} + 1 \frac{23}{24}$
Given :
The given expression is $3 \frac{7}{9} + 5 \frac{7}{8} + 1 \frac{23}{24}$
To do :
We have to simplify the given expression.
Solution :
$3 \frac{7}{9} + 5 \frac{7}{8} + 1 \frac{23}{24}$
Convert mixed fractions into normal fractions,
$3 \frac{7}{9} = \frac{9\times3 +7}{9} = \frac{27+7}{9} = \frac{34}{9}$
$5 \frac{7}{8} = \frac{8\times5 +7}{8} = \frac{40+7}{8} = \frac{47}{8}$
$1 \frac{23}{24} = \frac{24\times1 +23}{24} = \frac{24+23}{24} = \frac{47}{24}$
now add,
$\frac{34}{9} + \frac{47}{8} + \frac{47}{24}$
Denominators are different, to make them equal, take LCM
LCM of 9 , 8 , 24 is 72
$\frac{34\times8}{9\times8} + \frac{47\times9}{8\times9} + \frac{47\times3}{24\times3}$
$\frac{272}{72} + \frac{423}{72} + \frac{141}{72}$
now the denominators are same,
$\frac{272 + 423 + 141}{72}$
$\frac{836}{72} = 11 \frac{44}{72}$
$3 \frac{7}{9} + 5 \frac{7}{8} + 1 \frac{23}{24} = 11 \frac{44}{72}$
The value of $3 \frac{7}{9} + 5 \frac{7}{8} + 1 \frac{23}{24}$ is $ 11 \frac{44}{72}$