Simplify the following:
$3^0 + (-4)^{-1} \times 2^2$.

Academic Mathematics NCERT Class 8

Given :

The given expression is $3^0 + (-4)^{-1} \times 2^2$.

To do :

We have to simplify the given expression.

Solution :

$3^0 + (-4)^{-1} \times 2^2$

$3^0 + (-4)^{-1} \times 2^2= 1 + \frac{1}{-4} \times 4$ $[a^0 = 1 ; a^{-m} = \frac{1}{a^m}]$

$= 1 -1 = 0$.

Therefore, the value of $3^0 + (-4)^{-1} \times 2^2$ is 0.

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Updated on: 10-Oct-2022

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