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Simplify the following expressions:$ (\sqrt{3}+\sqrt{7})^{2} $
Given:
\( (\sqrt{3}+\sqrt{7})^{2} \)
To do:
We have to simplify the given expression.
Solution:
We know that,
$(a+b)(a-b)=a^2-b^2$
$(a+b)^2=a^2+2ab+b^2$
$(a-b)^2=a^2-2ab+b^2$
Therefore,
$(\sqrt{3}+\sqrt{7})^{2}=(\sqrt{3})^{2}+(\sqrt{7})^{2}+2 \times \sqrt{3} \times \sqrt{7}$
$=3+7+2 \sqrt{3\times7}$
$=10+2 \sqrt{21}$
Hence, $(\sqrt{3}+\sqrt{7})^{2}=10+2 \sqrt{21}$.
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