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Simplify the following:
$ \frac{3^n \times 9^{n+1}}{3^{n-1} \times 9^{n-1}} $
Given:
\( \frac{3 n \times 9^{n+1}}{3^{n-1} \times 9^{n-1}} \)
To do:
We have to simplify the given expression.
Solution:
We know that,
$(a^{m})^{n}=a^{m n}$
$a^{m} \times a^{n}=a^{m+n}$
$a^{m} \div a^{n}=a^{m-n}$
$a^{0}=1$
$\frac{3^n \times 9^{n+1}}{3^{n-1} \times 9^{n-1}}=\frac{3^{n} \times(3^{2})^{n+1}}{3^{n-1} \times(3^{2})^{n-1}}$
$=\frac{3^{n} \times 3^{2 n+2}}{3^{n-1} \times 3^{2 n-2}}$
$=3^{2 n+2+n-n+1-2 n+2}$
$=3^{3 n-3 n+2+3}$
$=3^{5}$
$=243$
Therefore, $\frac{3 n \times 9^{n+1}}{3^{n-1} \times 9^{n-1}}=243$.
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