Simplify the following:

$ \frac{\left(3^{3}\right)^{2} \times 5^{2}}{9^{2} \times 5} $

Academic Mathematics NCERT Class 7

Given: $\frac{\left(3^{3}\right)^{2} \times 5^{2}}{9^{2} \times 5}$

Solution:

$\frac{\left(3^{3}\right)^{2} \times 5^{2}}{9^{2} \times 5}$

Cancel the common factor: 5

$=\frac{5\left(3^{3}\right)^{2}}{9^{2}}$

$\left(3^{3}\right)^{2}=3^{6}$

$=\frac{3^{6} \times 5}{9^{2}}$

We know $9^{2}: 3^{4}$

$=\frac{3^{6} \times 5}{3^{4}}$

Cancel common factors :$\frac{5 \times 3^{6}}{3^{4}}: 3^{2} \times 5$

$=3^{2} \times 5$

$3^{2}=9$

$=9 \times 5$

$=45$

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Updated on: 10-Oct-2022

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