Simplify the following
$ 4^{3} \times\left(x^{4}\right) \times 6 x^{3} \p 2 x^{2} $

Given:

\( 4^{3} \times\left(x^{4}\right) \times 6 x^{3} \div 2 x^{2} \)

To do:

We have to find the value of $x$.

Solution:

We know that,

$(a^{m})^{n}=a^{m n}$

$a^{m} \times a^{n}=a^{m+n}$

$a^{m} \div a^{n}=a^{m-n}$

$a^{0}=1$  

Therefore,

$ \begin{array}{l}
4^{3} \times x^{4} \times 6x^{3} \div 2x^{2} =( 4\times 6\div 2)\left( x^{4+3-2}\right)\\
=( 2\times 6)\left( x^{7-2}\right)\\
=12x^{5}
\end{array}$

Tutorialspoint

Simply Easy Learning

Updated on: 10-Oct-2022

37 Views

Kickstart Your Career

Get certified by completing the course

Get Started