Simplify the expression and find its values if $a=-1, b=-3$.$4 a^{2}-b^{2}+6 a^{2}-7 b^{2}$
Given :
The given expression is $4 a^{2}-b^{2}+6 a^{2}-7 b^{2}$; $a=-1, b=-3$.
To do :
We have to simplify the expression and find its value.
Solution :
$4 a^{2}-b^{2}+6 a^{2}-7 b^{2}$.
$4 a^{2}-b^{2}+6 a^{2}-7 b^{2} = 4 a^{2}+6 a^{2}-7 b^{2}-b^{2}$
$ = 10 a^2 - 8 b^2$
Substitute $a=-1, b=-3$ in the given expression.
$10 a^2 - 8 b^2$
$ = 10 (-1)^2 - 8 (-3)^2$
$= 10 (1) - 8 (9)$
$ = 10 - 72 = -62$.
Therefore, the value of given expression is $-62$.
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