Simplify:
$(x^3 - 2x^2 + 3x - 4) (x - 1) - (2x - 3) (x^2 - x + 1)$
Given:
$(x^3 - 2x^2 + 3x - 4) (x - 1) - (2x - 3) (x^2 - x + 1)$
To do:
We have to simplify the given expression.
Solution:
$(x^3 - 2x^2 + 3x - 4) (x - 1) - (2x - 3) (x^2 - x + 1)=[x(x^3 - 2x^2 + 3x - 4) - 1 (x^3 - 2x^2 + 3x - 4)] - [2x (x^2 - x + 1) - 3 (x^2 - x + 1)]$
$= [x^4 - 2x^3 + 3x^2 - 4x - x^3 + 2x^2 - 3x + 4]-[2x^3 - 2x^2 + 2x - 3x^2 + 3x - 3]$
$= (x^4 - 2x^3 - x^3 + 3x^2 + 2x^2 - 4x - 3x + 4)-(2x^3 - 2x^2 - 3x^2 + 2x + 3x - 3)$
$= (x^4 - 3x^3 + 5x^2 - 7x + 4) - (2x^3 - 5x^2 + 5x - 3)$
$= x^4 - 3x^3 + 5x^2 - 7x + 4 - 2x^3 + 5x^2 - 5x + 3$
$= x^4 - 3x^3 - 2x^3 + 5x^2 + 5x^2 - 7x - 5x + 4 + 3$
$= x^4 - 5x^3 + 10x^2 - 12x + 7$
Related Articles
- Simplify:$(3x- 2) (2x - 3) + (5x - 3) (x + 1)$
- Simplify: $( 3x\ +\ 4)( 2x\ -\ 3) \ +\ ( 5x\ -\ 4)( x\ +\ 2)$
- Simplify:(i) $2x^2 (x^3 - x) - 3x (x^4 + 2x) -2(x^4 - 3x^2)$(ii) $x^3y (x^2 - 2x) + 2xy (x^3 - x^4)$(iii) $3a^2 + 2 (a + 2) - 3a (2a + 1)$(iv) $x (x + 4) + 3x (2x^2 - 1) + 4x^2 + 4$(v) $a (b-c) - b (c - a) - c (a - b)$(vi) $a (b - c) + b (c - a) + c (a - b)$(vii) $4ab (a - b) - 6a^2 (b - b^2) -3b^2 (2a^2 - a) + 2ab (b-a)$(viii) $x^2 (x^2 + 1) - x^3 (x + 1) - x (x^3 - x)$(ix) $2a^2 + 3a (1 - 2a^3) + a (a + 1)$(x) $a^2 (2a - 1) + 3a + a^3 - 8$(xi) $\frac{3}{2}-x^2 (x^2 - 1) + \frac{1}{4}-x^2 (x^2 + x) - \frac{3}{4}x (x^3 - 1)$(xii) $a^2b (a - b^2) + ab^2 (4ab - 2a^2) - a^3b (1 - 2b)$(xiii) $a^2b (a^3 - a + 1) - ab (a^4 - 2a^2 + 2a) - b (a^3- a^2 -1)$.
- Simplify the following:$(3x+4)(2x-3)+(5x-4)(x+2)$.
- Solve for $x$:$\frac{1}{x}+\frac{2}{2x-3}=\frac{1}{x-2}, x≠0, \frac{3}{2}, 2$
- Simplify the following :$( 3 x^2 + 5 x - 7 ) (x-1) - ( x^2 - 2 x + 3 ) (x + 4)$
- Simplify:$(x^3 - 2x^2 + 5x-7) (2x-3)$
- Simplify:$(5x + 3) (x - 1) (3x - 2)$
- Solve the following quadratic equation by factorization: $\frac{x+1}{x-1}+\frac{x-2}{x+2}=4-\frac{2x+3}{x-2}, x ≠ 1, -2, 2$
- Simplify:$(x^2-3x + 2) (5x- 2) - (3x^2 + 4x-5) (2x- 1)$
- Check whether the following are quadratic equations:(i) \( (x+1)^{2}=2(x-3) \)(ii) \( x^{2}-2 x=(-2)(3-x) \)(iii) \( (x-2)(x+1)=(x-1)(x+3) \)(iv) \( (x-3)(2 x+1)=x(x+5) \)(v) \( (2 x-1)(x-3)=(x+5)(x-1) \)(vi) \( x^{2}+3 x+1=(x-2)^{2} \)(vii) \( (x+2)^{3}=2 x\left(x^{2}-1\right) \)(viii) \( x^{3}-4 x^{2}-x+1=(x-2)^{3} \)
- Factorize $(x+1) (x+2) (x+3) (x+6) - 3x^2$.
- Determine which of the following polynomials has \( (x+1) \) a factor:(i) \( x^{3}+x^{2}+x+1 \)(ii) \( x^{4}+x^{3}+x^{2}+x+1 \)(iii) \( x^{4}+3 x^{3}+3 x^{2}+x+1 \)(iv) \( x^{3}-x^{2}-(2+\sqrt{2}) x+\sqrt{2} \)
- If \( x+\frac{1}{x}=3 \), calculate \( x^{2}+\frac{1}{x^{2}}, x^{3}+\frac{1}{x^{3}} \) and \( x^{4}+\frac{1}{x^{4}} \).
- Solve for $x$:$\frac{x-1}{x-2}+\frac{x-3}{x-4}=3\frac{1}{3}, x≠2, 4$
Kickstart Your Career
Get certified by completing the course
Get Started