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Simplify:
$ \left\{3^{-1} \times(-4)^{-1}\right\} \times 6^{-1} $
Given:
\( \left\{3^{-1} \times(-4)^{-1}\right\} \times 6^{-1} \)
To do:
We have to simplify \( \left\{3^{-1} \times(-4)^{-1}\right\} \times 6^{-1} \).
Solution:
We know that,
$a^{-m}=\frac{1}{a^m}$
Therefore,
${3^{-1} \times(-4)^{-1}} \times 6^{-1}=(\frac{1}{3}\times\frac{1}{-4}) \times \frac{1}{6}$
$=\frac{1}{3\times-4\times6}$
$=-\frac{1}{72}$
Hence, ${3^{-1} \times(-4)^{-1}} \times 6^{-1}=-\frac{1}{72}$.
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