Simplify:
$\frac{7^8\times a^{10}b^7c^{12}}{7^6\times a^8b^4c^{12}}$

Given:

$\frac{7^8\times a^{10}b^7c^{12}}{7^6\times a^8b^4c^{12}}$

To do:

We have to simplify the given expression.

Solution:

We know that,

$\frac{a^m}{a^n}=a^{m-n}$ 

Therefore,

$\frac{7^8\times a^{10}b^7c^{12}}{7^6\times a^8b^4c^{12}}=7^{(8-6)}\times a^{(10-8)}b^{(7-4)}c^{(12-12)}$

$=7^2\times a^2b^3c^0$

$=49a^2b^3$   (Since $c^0=1$)

Hence, $\frac{7^8\times a^{10}b^7c^{12}}{7^6\times a^8b^4c^{12}}=49a^2b^3$.

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Updated on: 10-Oct-2022

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