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Simplify:
$( 3x\ +\ 4)( 2x\ -\ 3) \ +\ ( 5x\ -\ 4)( x\ +\ 2)$
Given:
$( 3x\ +\ 4)( 2x\ -\ 3) \ +\ ( 5x\ -\ 4)( x\ +\ 2)$
To simplify:
We have to find the value of $( 3x\ +\ 4)( 2x\ -\ 3) \ +\ ( 5x\ -\ 4)( x\ +\ 2)$
Solution:
$(3x\ +\ 4)(2x\ -\ 3)\ +\ (5x\ -\ 4)(x\ +\ 2)$
$=\ 3x(2x\ -\ 3)\ +\ 4(2x\ -\ 3)\ +\ 5x(x\ +\ 2)\ -\ 4(x\ +\ 2)$
$=\ 6x^{2} \ -\ 9x\ +\ 8x\ -\ 12\ +\ 5x^{2} \ +\ 10x\ -\ 4x\ -\ 8$
$=\ \mathbf{11x^{2} \ -\ 5x\ -\ 20}$
So, the answer is $\mathbf{11x^{2} \ -\ 5x\ -\ 20}$.
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