Savitha walks $ \frac{2}{3} \mathrm{~km} $ from a place P towards east and then from there $\frac{12}{7}\ km$ towards west. Where will be she now?

Given:

Savitha walks \( \frac{2}{3} \mathrm{~km} \) from a place P, towards east and then from there \( \frac{12}{7} \) km towards west.

To do:

We have to find the final position of Savitha from P. 

Solution:

 Let P be the origin, the movement towards East be positive and the movement towards the West be negative.

Therefore,

The final position of Savitha from P$=\frac{2}{3}-\frac{12}{7}$

$=\frac{2\times7-3\times12}{21}$   (LCM of 3 and 7 is 21)

$=\frac{14-36}{21}$

$=\frac{-22}{21}$

$=-1\frac{1}{21}$

This implies,

Savitha is $1\frac{1}{21}$ km West of P.

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Updated on: 10-Oct-2022

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