Satpal walks $ \frac{2}{3} \mathrm{~km} $ from a place P, towards east and then from there $ 1 \frac{5}{7} $ km towards west. Where will he be now from $ P ? $

Given:

Satpal walks \( \frac{2}{3} \mathrm{~km} \) from a place P, towards east and then from there \( 1 \frac{5}{7} \) km towards west.

To do:

We have to find the final position of Satpal from P.

Solution:

 Let P be the origin, the movement towards East be positive and the movement towards the West be negative.

Therefore,

The final position of Satpal from P$=\frac{2}{3}-1\frac{5}{7}$

$=\frac{2}{3}-\frac{1\times7+5}{7}$

$=\frac{2}{3}-\frac{12}{7}$

$=\frac{2\times7-3\times12}{21}$   (LCM of 3 and 7 is 21)

$=\frac{14-36}{21}$

$=\frac{-22}{21}$

$=-1\frac{1}{21}$

This implies,

Satpal is $1\frac{1}{21}$ km West of P.

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Updated on: 10-Oct-2022

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