Represent $\sqrt{5}$ on the number line.


Given :

The given number is $\sqrt{5}$.

To do :

We have to represent $\sqrt{5}$ on the number line.

Solution :

To solve this question, we should use the Pythagoras theorem.

$Hypotenuse^2 = Base^2 + Height^2$


  • Now first draw a number line and mark '0', '1', and '2'.
  • With 1 unit as length draw a line from '2'  such that it is perpendicular to the line.
  • Now join the point (0) and the end of a new line of 1 unit length.
  • A right-angled triangle is constructed.
  • Now let us name the triangle as ABC such that BC is the height (perpendicular), AB is the base of the triangle and AC is the hypotenuse of the right-angled triangle ABC.

You know, $AC^2 = 2^2 + 1^2$

                    $AC^2 = 4+1 = 5$

                    $AC = \sqrt{5}$

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AC2=22+12 A C^{2}=2^{2}+1^{2} " role="presentation" style="display: inline-table; line-height: normal; font-size: 16.94px; word-spacing: normal; overflow-wrap: normal; white-space: nowrap; float: none; direction: ltr; max-width: none; max-height: none; min-width: 0px; min-height: 0px; border: 0px; padding: 0px; margin: 0px; position: relative;"> A C^{2}=2^{2}+1^{2}" role="presentation" style="transition: none 0s ease 0s; display: inline; position: relative; border: 0px; padding: 0px; margin: 0px; vertical-align: 0px; line-height: normal;">A C^{2}=2^{2}+1^{2}, 


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Updated on: 10-Oct-2022

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