Replace $ ^{\star} $ by a digit in $388^{\star} 62$ so that the number is divisible by 9.

Given :

The given number is $388^{\star} 62$.

To do :

We have to replace $ ^{\star} $ by a digit in $388^{\star} 62$ so that the number is divisible by 9.

Solution :

To be divisible by 9, the number obtained by adding the digits of the number should be divisible by both 3 and 9.

Sum of digits of the  given number  $388^{\star} 62 = 3 + 8 + 8 + ^{\star} + 6 + 2 = 27+^{\star}$

This is divisible by 9 if $^{\star}$ is either 0 or 9

that is the number becomes either 388062 or 388962

Therefore, the $^{\star}$ can be replaced by 0 or 9;