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Replace $ ^{\star} $ by a digit in $388^{\star} 62$ so that the number is divisible by 9.
Given :
The given number is $388^{\star} 62$.
To do :
We have to replace $ ^{\star} $ by a digit in $388^{\star} 62$ so that the number is divisible by 9.
Solution :
To be divisible by 9, the number obtained by adding the digits of the number should be divisible by both 3 and 9.
Sum of digits of the given number $388^{\star} 62 = 3 + 8 + 8 + ^{\star} + 6 + 2 = 27+^{\star}$
This is divisible by 9 if $^{\star}$ is either 0 or 9
that is the number becomes either 388062 or 388962
Therefore, the $^{\star}$ can be replaced by 0 or 9;
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