Pulkit's salary was Rs 35,000. He got a raise of Rs 7,000. Reena's salary was Rs 24,000. She was given a raise of Rs 6,000. Find what fraction of the original income the raise was for each and which one of the two got a higher raise.

Given :

Salary of Pulkit = Rs. 35,000

Raise in salary of Pulkit = Rs. 7,000

Salary of Reena = Rs. 24,000

Raise in salary of Reena = Rs. 6,000

To find :

We have to find what fraction of the original income the raise was for each and which one of the two got a higher raise.

Solution :

The fractional raise in salary for Pulkit = $\frac{7000}{35000}=\frac{1}{5}.$

The fractional raise in salary for Reena = $\frac{6000}{24000}=\frac{1}{4}.$

We know that,

If a > b then $\frac{1}{a}<\frac{1}{b}$  where a and b are positive integers.

Therefore,

5>4 implies $\frac{1}{5}<\frac{1}{4}$

This implies,

Reena got a higher raise.