Prove that the tangents drawn at the end points of a chord of a circle make equal angles with the chord.


Given: Two tangents drawn at the end points of a chord of a circle.

To do: The tangents make equal angles with the chord. 

Solution:

Need to prove that $\angle BAP\ =\angle \ ABP$

$AB$ is the chord.

We know that $OA = OB\ ( radius)$

$\angle OBP=\angle OAP=90^{o}$

Join $OP$ and 

$OP=OP$

By SAS congruency

$\vartriangle OBP\cong \vartriangle OAP$

$\therefore \ BP=AP$

Angles opposite to equal sides are equal.

$\therefore \angle BAP=\angle ABP$

Hence proved $\angle BAP=\angle ABP$

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Updated on: 10-Oct-2022

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