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Prove that $4 − 5\sqrt{2}$ is an irrational number.
Given: $4\ −\ 5\sqrt{2}$
To do: Here we have to prove that $4\ −\ 5\sqrt{2}$ is an irrational number.
Solution:
Let us assume, to the contrary, that $4\ −\ 5\sqrt{2}$ is rational.
So, we can find integers a and b ($≠$ 0) such that $4\ −\ 5\sqrt{2}\ =\ \frac{a}{b}$.
Where a and b are co-prime.
Now,
$4\ −\ 5\sqrt{2}\ =\ \frac{a}{b}$
$4\ -\ \frac{a}{b}\ =\ 5\sqrt{2}$
$\frac{4b\ -\ a}{b}\ =\ 5\sqrt{2}$
$\frac{4b\ -\ a}{5b}\ =\ \sqrt{2}$
Here, $\frac{4b\ -\ a}{5b}$ is a rational number but $\sqrt{2}$ is irrational number.
But, Rational number $≠$ Irrational number.
This contradiction has arisen because of our incorrect assumption that $4\ −\ 5\sqrt{2}$ is rational.
So, this proves that $4\ −\ 5\sqrt{2}$ is an irrational number.
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