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Pick out the solution from the values given in the bracket next to each equation. Show that the other values do not satisfy the equation.
(a) $ 5 m=60 $ $ (10,5,12,15) $
(b) $ n+12=20 $ $ (12,8,20,0) $
(c) $ p-5=5 $ $ (0,10,5-5) $
(d) $ \frac{q}{2}=7 $ $ (7,2,10,14) $
(e) $ r-4=0 $ $ (4,-4,8,0) $
(f) $ x+4=2 $ $ (-2,0,2,4) $
To do:
We have to pick out the solution from the values given in the bracket next to each equation.
Solutions:
(a) $5m = 60$
If $m = 10$ then $5m=5(10)=50$
$m=10$ is not a solution for the equation $5m = 60$
Therefore, the equation is not satisfied.
If $m = 5$ then $5m=5(5)=25$
$m=5$ is not a solution for the equation $5m = 60$
Therefore, the equation is not satisfied.
If $m = 12$ then $5m=5(12)=60$
$m=12$ is a solution for the equation $5m = 60$
Therefore, the equation is satisfied.
If $m = 15$ then $5m=5(15)=75$
$m=15$ is not a solution for the equation $5m = 60$
Therefore, the equation is not satisfied.
(b) $n + 12 = 20$
If $n = 12$ then $n+12=12+12=24$
$n=12$ is not a solution for the equation $n+12 = 20$
Therefore, the equation is not satisfied.
If $n = 8$ then $n+12=8+12=20$
$n=8$ is a solution for the equation $n+12 = 20$
Therefore, the equation is satisfied.
If $n = 20$ then $n+12=20+12=32$
$n=20$ is not a solution for the equation $n+12 = 20$
Therefore, the equation is not satisfied.
If $n = 0$ then $n+12=0+12=12$
$n=0$ is not a solution for the equation $n+12 = 20$
Therefore, the equation is not satisfied.
(c) $p - 5 = 5$
If $p = 0$ then $p-5=0-5=-5$
$p=0$ is not a solution for the equation $p-5 = 5$
Therefore, the equation is not satisfied.
If $p = 10$ then $p-5=10-5=5$
$p=10$ is a solution for the equation $p-5 = 5$
Therefore, the equation is satisfied.
If $p = 5$ then $p-5=5-5=0$
$p=5$ is not a solution for the equation $p-5 = 5$
Therefore, the equation is not satisfied.
If $p = -5$ then $p-5=-5-5=-10$
$p=-5$ is not a solution for the equation $p-5 = 5$
Therefore, the equation is not satisfied.
(d) $\frac{q}{2} = 7$
If $q = 7$ then $\frac{q}{2}=\frac{7}{2}$
$q=7$ is not a solution for the equation $\frac{q}{2} = 7$
Therefore, the equation is not satisfied.
If $q = 2$ then $\frac{q}{2}=\frac{2}{2}=1$
$q=2$ is not a solution for the equation $\frac{q}{2} = 7$
Therefore, the equation is not satisfied.
If $q = 10$ then $\frac{q}{2}=\frac{10}{2}=5$
$q=10$ is not a solution for the equation $\frac{q}{2} = 7$
Therefore, the equation is not satisfied.
If $q = 14$ then $\frac{q}{2}=\frac{14}{2}=7$
$q=14$ is a solution for the equation $\frac{q}{2} = 7$
Therefore, the equation is satisfied.
(e) $r - 4 = 0$
If $r = 4$ then $r-4=4-4=0$
$r=4$ is a solution for the equation $r-4 = 0$
Therefore, the equation is satisfied.
If $r = -4$ then $r-4=-4-4=-8$
$r=-4$ is not a solution for the equation $r-4 = 0$
Therefore, the equation is not satisfied.
If $r = 8$ then $r-4=8-4=4$
$r=8$ is not a solution for the equation $r-4 = 0$
Therefore, the equation is not satisfied.
If $r = 0$ then $r-4=0-4=-4$
$r=0$ is not a solution for the equation $r-4 = 0$
Therefore, the equation is not satisfied.
(f) $x + 4 = 2$
If $x = -2$ then $x+4=-2+4=2$
$x=-2$ is a solution for the equation $x+4 = 2$
Therefore, the equation is satisfied.
If $x = 0$ then $x+4=0+4=4$
$x=0$ is not a solution for the equation $x+4 = 2$
Therefore, the equation is not satisfied.
If $x = 2$ then $x+4=2+4=6$
$x=2$ is not a solution for the equation $x+4 = 2$
Therefore, the equation is not satisfied.
If $x = 4$ then $x+4=4+4=8$
$x=4$ is not a solution for the equation $x+4 = 2$
Therefore, the equation is not satisfied.
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