One of the angles of a triangle is 75 degrees. If the difference of the other two is 35 degrees then the largest angle of the triangle has a measure of_____.
Given:
One of the angles of a triangle is 75 degrees.
The difference of other two is 35 degrees.
To do:
We have to find the measure of the largest angle.
Solution:
Let $ABC$ be the triangle in which $\angle A=75^o$ and $\angle B>\angle C$.
By angle sum property of the triangle,
$\angle A+\angle B+\angle C=180^o$
$75^o+\angle B+\angle C=180^o$
$\angle B+\angle C=180^o-75^o=105^o$......(i)
According to the question,
$\angle B-\angle C=35^o$............(ii)
Adding (i) and (ii), we get,
$\angle B+\angle C+\angle B-\angle C=105^o+35^o$
$2\angle B=140^o$
$\angle B=70^o$
This implies,
$70^o+\angle C=105^o$
$\angle C=105^o-70^o=35^o$
The measure of the largest angle is $75^o$.
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