On a level road, a scooterist applies brakes to slow down from a speed of $10\ m/s$ to $5\ m/s$. If the mass of the scooterist and the scooter be $150\ kg$, calculate the work done by the brakes. (Neglect air resistance and friction)

Here given, mass of the scooterist and scooter $m=150\ kg$

Initial velocity of the scooter $v_1=10\ m/s$

Final velocity $v_2=5\ m/s$

Therefore, work done by the brakes to reduce the velocity of the scooter will be equal to the change of the kinetic energy of the scooter.

So, $W=K_1-K_2$

$=\frac{1}{2}m(v_1^2-v_2^2)$

$=\frac{1}{2}\times150(10^2-5^2)$

$=75\times75$

$=5625\ Joule$

Therefore, work done by the brakes to reduce the velocity of the scooter will be $5625\ Joule$.

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Updated on: 10-Oct-2022

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