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Observe the following pattern
$1 + 3 = 2^2$
$1 + 3 + 5 = 3^2$
$1+3 + 5 + 7 = 4^2$
and write the value of $1 + 3 + 5 + 7 + 9 +…………$ upto $n$ terms.
Given:
$1 + 3 = 2^2$
$1 + 3 + 5 = 3^2$
$1+3 + 5 + 7 = 4^2$
To do:
We have to write the value of $1 + 3 + 5 + 7 + 9 +…………$ upto $n$ terms.
Solution:
We can observe that sum of first two odd numbers is $2^2$
Sum of first three odd numbers is $3^2$
Sum of first four odd numbers is $4^2$
This implies,
Sum of first $n$ odd numbers $=n^2$.
Therefore,
$1 + 3 + 5 + 7 + 9 +…………$ upto $n$ terms is $n^2$.
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