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Na+ has completely filled K and L shells. Explain.
Sodium atom (Na), has atomic number =11
Number of protons =11
Number of electrons = 11
Electronic configuration of Na = K L M – 2 8 1
Sodium atom (Na) loses 1 electron to become stable and form Na+ ion. Hence it has completely filled K and L shells.
[Extra information: The rules for the writing of the distribution of electrons in various shells for the first eighteen elements are given below:
(i) The maximum number of electrons present in a shell is given by the formula-2 n2
∵ n = orbit number i.e., 1, 2, 3
∵ The maximum number of electrons in different shells are:
K shell n = 1 2n2 => 2(1)2 = 2
L shell n = 2 2n2 => 2(2)2 = 8
M shell n = 3 2n2 => 2(3)2 = 18
N shell n = 4 2n2 => 2(4)2 = 32
(ii) The maximum number of electrons that can be accommodated in the outermost orbit is 8.
(iii) Electrons are not accommodated in a given shell unless the inner shells are filled.]
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