# N resistors of resistance R are connected in series and than in parallel .What will be the ratio of resistance in both the cases?

**In series**
Resistance (Series) = R1+R2+....Rn.

Here R1=R2=....=R

So net resistance=nR

**In parallel** $\frac{1}{Resistance(Parallel)}=\frac{1}{R1} + \frac{1}{R2} + ....... \frac{1}{Rn}$

R1=R2=... =R

So $\frac{1}{Resistance(parallel)}= \frac{n}{R}$

$R(parallel)=\frac{R}{n}$

So ratio of series and parallel= $\frac{nR }{ (R/n)}$

$= n^2$

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