Multiply $\frac{6}{13}$ by the reciprocal of $\frac{-7}{16}$.

Given:

The given fractions are $\frac{6}{13}$ and $\frac{-7}{16}$.

To do:

We have to multiply $\frac{6}{13}$ by the reciprocal of $\frac{-7}{16}$.

Solution:

The reciprocal of a number $\frac{a}{b}$ is $\frac{b}{a}$.

Therefore,

Reciprocal of $\frac{-7}{16}$ is $\frac{16}{-7}$.

$\frac{6}{13} \times \frac{16}{-7} = -\frac{(6\times 16)}{(13\times 7)}$

$= - \frac{96}{91}$

Therefore, the resultant fraction is $-\frac{96}{91}$.

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Updated on: 10-Oct-2022

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