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Multiply:
$(x^6-y^6)$ by $(x^2+y^2)$
To do:
We have to multiply $(x^6-y^6)$ by $(x^2+y^2)$
Solution:
We know that,
$(a+b)\times(c+d)=a(c+d)+b(c+d)$
Therefore,
$(x^6-y^6)\times(x^2+y^2)=x^6 (x^2 + y^2) - y^6 (x^2 + y^2)$
$= x^6(x^2) + x^6y^2 - x^2y^6 -y^6(y^2)$
$= x^{6+2} + x^6y^2 - x^2y^6 - y^{6+2}$
$=x^8 + x^6y^2 - x^2y^6 - y^8$
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