Multiply:
$(x^6-y^6)$ by $(x^2+y^2)$

To do:

We have to multiply $(x^6-y^6)$ by $(x^2+y^2)$

Solution:

We know that,

$(a+b)\times(c+d)=a(c+d)+b(c+d)$

Therefore,

$(x^6-y^6)\times(x^2+y^2)=x^6 (x^2 + y^2) - y^6 (x^2 + y^2)$

$= x^6(x^2) + x^6y^2 - x^2y^6 -y^6(y^2)$

$= x^{6+2} + x^6y^2 - x^2y^6 - y^{6+2}$

$=x^8 + x^6y^2 - x^2y^6 - y^8$