Multiply:
$(x^2 + y^2)$ by $(3a+2b)$

To do:

We have to multiply $(x^2 + y^2)$ by $(3a+2b)$

Solution:

We know that,

$(a+b)\times(c+d)=a(c+d)+b(c+d)$

Therefore,

$(x^2 + y^2)\times(3a+2b)=x^2(3a + 2b) + y^2 (3a + 2b)$

$= 3x^2a + 2x^2b + 3y^2a + 2y^2b$

$=3ax^2 + 3ay^2 + 2bx^2 + 2by^2$

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Updated on: 10-Oct-2022

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