Multiply
$1+6x^{2} - 4x^{3} \times (3x-y)$

Given: $1+6x^{2} - 4x^{3} \times (3x-y)$

To do:  Multiply the expression 

Solution: 

$1+6x^{2} - 4x^{3} \times (3x-y)$

By using distributive law

= $1 \times (3x-y)+6x^{2} \times (3x-y) - 4x^{3} \times (3x-y)$

= $3x-y+6x^{3} -6y - 12x^{4} -4x^{3}y$

=$-12x^{4}+6x^{3} -4x^{3}y+3x-7y$

Therefore teh solution to the expression  $1+6x^{2} - 4x^{3} \times (3x-y)$ is $-12x^{4}+6x^{3} -4x^{3}y+3x-7y$

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Updated on: 10-Oct-2022

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