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# Mitesh, Mihir, Siddharth and Prashant paid a bill of restaurant unequally. The ratio of amount paid by Mitesh to Mihir is 7:8. Siddharth paid half the amount Mihir paid and Prashant paid half the amount Siddharth paid. If the bill amount is Rs. 2100, find the amount paid by each.

**Given:**

The ratio of amount paid by Mitesh to Mihir is 7:8 Siddharth paid half the amount Mihir paid and Prashant paid half the amount Siddharth paid.

Total bill amount$=$Rs. 2100

**To do:**

We have to find the amount paid by each person.

**Solution:**

Let the amount paid by Mitesh and Mihir be $7x$ and $8x$ respectively.

This implies,

Amount paid by Sidhharth$= \frac{8x}{2}=4x$

Amount paid by Prashant $=\frac{4x}{2}=2x$

Therefore,

$7x+8x+4x+2x= 2100$

$21x= 2100$

$x= \frac{2100}{21}$

$x= 100$

The amount paid by Mitesh$=7x=7(100)=Rs. 700$.

The amount paid by Mihir$=8x=8(100)=Rs. 800$.

The amount paid by Siddharth$=4x=4(100)=Rs. 400$.

The amount paid by Prashant$=2x=2(100)=Rs. 200$.

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