$ \mathrm{ABC} $ and $ \mathrm{ADC} $ are two right triangles with common hypotenuse $ \mathrm{AC} $. Prove that $ \angle \mathrm{CAD}=\angle \mathrm{CBD} $.
Given:
\( \mathrm{ABC} \) and \( \mathrm{ADC} \) are two right triangles with common hypotenuse \( \mathrm{AC} \).
To do:
We have to prove that \( \angle \mathrm{CAD}=\angle \mathrm{CBD} \).
Solution:
We know that,
Angles in the same segment are equal.
This implies,
$\angle CBD=\angle CAD$
Hence proved.
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