Let there be an A.P. with first term ‘$a$’, common difference '$d$'. If $a_n$ denotes its $n^{th}$ term and $S_n$ the sum of first $n$ terms, find.$n$ and $d$, if $a = 8, a_n = 62$ and $S_n = 210$.
Given:
In an A.P., first term $=a$ and common difference $=d$.
$a_n$ denotes its $n^{th}$ term and $S_n$ the sum of first $n$ terms.
To do:
We have to find $n$ and $d$, if $a = 8, a_n = 62$ and $S_n = 210$.
Solution:
We know that,
$\mathrm{S}_{n}=\frac{n}{2}[2 a+(n-1) d]$
$n$th term $a_n=a+(n-1)d$
This implies,
$a_n=8+(n-1)d$
$62=8+(n-1)d$
$62-8=(n-1)d$
$54=(n-1)d$
$(n-1)d=54$........(i)
$S_n=\frac{n}{2}[2 \times 8+(n-1)d]$
$210=\frac{n}{2}[16+54]$ (From (i))
$210(2)=n(70)$
$3(2)=n$
$n=6$
$\therefore (6-1)d=54$
$5d=54$
$d=\frac{54}{5}$
Therefore, $n=6$ and $d=\frac{54}{5}$. 
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