Let ABCD be a square of side $2a$. Find the coordinates of the vertices of this square whenA coincides with the origin and AB and AD are along OX and OY respectively.
Given:
ABCD is a square of side $2a$. A coincides with the origin and AB and AD are along OX and OY respectively.
To do:
We have to find the coordinates of the vertices of the square.
Solution:
We know that,
If a point lies on the x-axis then its y co-ordinate is $0$ and if the point lies on the y-axis, then its x co-ordinate is $0$.
A coincides with the origin $(0, 0)$, AB and AD are along OX and OY respectively
Co-ordinates of A, B, C and D are $(0, 0), (2a, 0), (2a, 2a)$ and $(0, 2a)$ respectively.
Therefore, the coordinates of the vertices of the square are $A\ (0,0), B\ (2a,0), C\ (2a,2a)$ and $D\ (0,2a)$.
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