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$ \left(\frac{x}{2}+\frac{3 y}{4}\right)\left(\frac{x}{2}+\frac{3 y}{4}\right) $
Given: $\left(\frac{x}{2} \ +\ \frac{3y}{4}\right) \ \times \ \left(\frac{x}{2} \ +\ \frac{3y}{4}\right)$
To find: We have to find the value of $\left(\frac{x}{2} \ +\ \frac{3y}{4}\right) \ \times \ \left(\frac{x}{2} \ +\ \frac{3y}{4}\right)$.
Solution:
$\left(\frac{x}{2} \ +\ \frac{3y}{4}\right) \ \times \ \left(\frac{x}{2} \ +\ \frac{3y}{4}\right)$
= $\left(\frac{x}{2} \ +\ \frac{3y}{4}\right)^{2}$
= $\left(\frac{x}{2}\right)^{2} \ +\ \left(\frac{3y}{4}\right)^{2} +2\times \left(\frac{x}{2}\right) \times \left(\frac{3y}{4}\right) \ $
= $\frac{x}{4}^{2} \ +\frac{9y}{4}^{2} +\left(\frac{3xy}{4}\right) \ $
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