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Keeping the p.d. constant, the resistance of a circuit is halved. The current will become:(a) one-fourth(b) four times(c) half(d) double
According to ohm's law:
$\mathrm{I}=\frac{\mathrm{V}}{\mathrm{R}}$
When V is constant,
$\mathrm{I} \propto \frac{\mathrm{1}}{\mathrm{R}}$
So, if resistance is halved, Current $I$ will be doubled.
Answer is (d) double
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