It is required to increase the velocity of a scooter of mass $80\ kg$ from $5$ to $25\ ms^{-1}$ in $2\ second$. Calculate the force required.

Here given, mass of the scooter $m=80\ kg.$

Initial velocity of the scooter $u=5\ ms^{-1}$

Final velocity of the scooter $v=25\ ms^{-1}$

Time $t=2\ s$

Therefore, acceleration $a=\frac{v-u}{t}$

$=\frac{25-5}{2}$

$=\frac{20}{2}$

$=10\ ms^{-2}$

Therefore, required force $F=ma$

$=80\ kg\times10\ ms^{-2}$

$=800\ N$

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Updated on: 10-Oct-2022

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